Additional comments related to material from the class. If anyone wants to convert this to a blog, let me know. These additional remarks are for your enjoyment, and will not be on homeworks or exams. These are just meant to suggest additional topics worth considering, and I am happy to discuss any of these further.
\(\int f = f - 1\) ==> \(f - \int f = 1.\)
Thus \((1 - \int) f = 1.\)
Therefore \(f = (1 - \int)^{-1} 1.\)
Using the geometric series expansion \((1-r)^{-1} = 1 + r + r^2 + \cdots\) with \( r = \int\) we find \(f = 1 + \int 1 + \int \int 1 + \int \int \int 1 + \cdots.\)
Now \(\int 1 = \int_{t=0}^{x} 1 dt = x.\)
Now \(\int \int 1 = \int(\int 1) = \int_{t=0}^{x} t dt = x^2/2 = x^2/2!.\)
Now \(\int \int \int 1 = \int(\ \int(\int 1)\ ) = \int_{t = 0}^{x} t^2/2 dt = x^3/3!.\)
We find \(f = f(x) = 1 + x + x^2/2! + x^3/3! + \cdots = e^x.\)
The big question is: can this be made rigorous, and if so how? Happy Thanksgiving!
Monday Nov 4: After finishing the last ingredient for the proof of the Riemann mapping theorem, we started our number theory tour by looking at the Riemann zeta function.